What is the calculated fault current for a short circuit in a 230V final subcircuit with an earth loop impedance of 0.32Ω?

To calculate the fault current during a short circuit in a low voltage system like a 230V final subcircuit, you can use Ohm's Law, where current (I) can be calculated as voltage (V) divided by impedance (Z). In this case, the voltage is 230V and the earth loop impedance is given as 0.32Ω.

Using the formula I = V / Z:

I = 230V / 0.32Ω

I = 718.75A

This calculation shows that the fault current flowing through the circuit at the moment of a short circuit would be 718.75A. This result helps in understanding the magnitude of current that could potentially flow in a fault situation, which is crucial for designing protective devices and ensuring the safety of the electrical installation.

The other options do not correctly represent the outcome of this calculation based on the values provided, making 718.75A the accurate determination of the fault current in the given scenario.